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Hyperbolic Functions
Exam Board: AQA Pearson Edexcel OCR WJEC / Eduqas CCEA
📌 Key Points
Key Fact: sinh x = (eˣ - e⁻ˣ)/2, cosh x = (eˣ + e⁻ˣ)/2, tanh x = sinh x/cosh x
Key Fact: Identities: cosh^2x - sinh^2x = 1, 1 - tanh^2x = sech^2x, sinh 2x = 2 sinh x cosh x, cosh 2x = cosh^2x + sinh^2x
Key Fact: Derivatives: d/dx(sinh x) = cosh x, d/dx(cosh x) = sinh x, d/dx(tanh x) = sech^2x
Key Fact: Integrals: ∫sinh x dx = cosh x + C, ∫cosh x dx = sinh x + C, ∫sech^2x dx = tanh x + C
Key Fact: Inverse functions: arsinh x = ln(x + sqrt(x^2+1)), arcosh x = ln(x + sqrt(x^2-1)) (x>=1), artanh x = ½ ln((1+x)/(1-x)) (|x|<1)
Key Fact: Osborn's rule: trig identity -> hyperbolic by changing sign of sin^2 terms
🎯 Learning Objectives
Define sinh, cosh, tanh, sech, cosech, coth in terms of exponentials Prove and use hyperbolic identities (analogous to trig identities) Differentiate and integrate hyperbolic functions Solve equations involving hyperbolic functions Use inverse hyperbolic functions and their logarithmic forms Apply hyperbolic functions to calculus problems (e.g. catenary)
💡 Worked Example
Exam-Style Question
Question: Solve 2 cosh x - 3 sinh x = 1
Model Answer:
2(eˣ+e⁻ˣ)/2 - 3(eˣ-e⁻ˣ)/2 = 1 -> eˣ+e⁻ˣ - 1.5(eˣ-e⁻ˣ) = 1 -> -0.5eˣ + 2.5e⁻ˣ = 1 -> multiply 2eˣ: -e^2ˣ + 5 = 2eˣ -> e^2ˣ + 2eˣ - 5 = 0 -> eˣ = -1 +/- sqrt6 -> eˣ = sqrt6 - 1 -> x = ln(sqrt6 - 1)
❓ Practice Questions Model answers are being added progressively - questions marked ✗ don't have one yet. Cross-check with your teacher or the official mark scheme.
Questions:
Prove: cosh 2x = 2cosh^2x - 1 = 1 + 2sinh^2x✗ answer coming soon ∫ sinh^2x dx✗ answer coming soon Solve: tanh x = ½✗ answer coming soon Find arsinh(2)✗ answer coming soon Show that the catenary y = cosh x has arc length ∫cosh x dx from a to b✗ answer coming soon
📄 Past Papers & Exam Resources
🔗 Further Reading & Resources
📚 Lesson Plan (50 minutes)
Starter (5 min): Recall prior knowledge of hyperbolic functions with quick questions.
Teaching (15 min): Work through each of the learning objectives, explaining principles step by step.
Key points review (5 min): Revisit the key points together, confirming understanding.
Worked example (10 min): Model the example question: Solve 2 cosh x - 3 sinh x = 1. Solution: 2(eˣ+e⁻ˣ)/2 - 3(eˣ-e⁻ˣ)/2 = 1 -> eˣ+e⁻ˣ - 1.5(eˣ-e⁻ˣ) = 1 -> -0.5eˣ + 2.5e⁻ˣ = 1 -> multiply 2eˣ: -e^2ˣ + 5 = 2eˣ -> e^2ˣ + 2eˣ - 5 = 0 -> eˣ = -1 +/- sqrt6 -> eˣ = sqrt6 - 1 -> x = ln(sqrt6 - 1)
Practice (10 min): Students attempt the practice questions independently; circulate and support.
Plenary (5 min): Review answers and address misconceptions.
🏠 Homework
Prove: cosh 2x = 2cosh^2x - 1 = 1 + 2sinh^2x ∫ sinh^2x dx Solve: tanh x = ½ Find arsinh(2) Show that the catenary y = cosh x has arc length ∫cosh x dx from a to b
🧾 Assessment
Check practice answers against the model answer; use the built-in practice questions as formative assessment.
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